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重复内容删除的小脚本

$
0
0

加入说序列式这样的

1 2
1 2
2 1
1 3
1 4
1 5
4 1

我们得出的结果如下:

1 3
1 5
2 1
4 1

程序如下:

use strict;
use warnings;

my $filename;
my %hash;
my @information;
my $key1;
my $key2;

print "please put in the file like this f:\\\\perl\\\\data.txt\n";
chomp($filename=<STDIN>);
open(IN,"$filename")||die("can not open");
while(<IN>)
{
	chomp;
	@information=split/\s+/,$_;
	if(exists $hash{$information[0]}{$information[1]})
	{
		next;
	}
	else
	{
	    $hash{$information[0]}{$information[1]}='A';
	}
}
close IN;

open(IN,"$filename")||die("can not open");
while(<IN>)
{
	@information=split/\s+/,$_;
	if(exists $hash{$information[1]}{$information[0]})
	{
		delete $hash{$information[0]}{$information[1]}
	}
	else
	{
		next;
	}
}
close IN;

open(OUT,">f:\\A_B_result.txt")||die("can not open");
foreach $key1 (sort{$a<=>$b} keys %hash)
{
	foreach $key2 (sort{$a<=>$b} keys %{$hash{$key1}})
	{
		print OUT "$key1 $key2\n";
	}
}
close OUT;


作者:gaorongchao1990626 发表于2012-12-28 21:32:05 原文链接
阅读:29 评论:0 查看评论

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