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高斯消元法(解齐次方程组)

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#define eps 1e-10
#define maxn 110
double equ[maxn][maxn], ans[maxn]; 
int n;

bool Gauss(){
    for( int i = 0; i < n; i ++ ){
        int pos = i;
        double res = fabs(equ[i][i]);
        for( int j = i + 1; j < n; j ++ )
            if( fabs(equ[j][i]) > res )
                pos = j, res = fabs(equ[j][i]);
        if( res < eps ) return false;
        if( pos != i ) for( int j = i; j<= n; j ++ )
            swap(equ[i][j], equ[pos][j]);
        for(  j = i + 1; j < n; j ++ ){
            res = equ[j][i] / equ[i][i];
            for( int k = i; k <= n; k ++ )
                equ[j][k] -= res * equ[i][k];
        }
    }
    for(  i = n - 1; i >= 0; i -- ) {
        ans[i] = equ[i][n];
        for( int j = n - 1; j > i; j -- )
            ans[i] -= equ[i][j] * ans[j];
        ans[i] /= equ[i][i];
    }
    return true;
}

作者:MetalSeed 发表于2013-2-4 23:32:36 原文链接
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