$ 0 0 select a.man_id,man_name,d.sex_name,zw_name,c.money from man as a left join zw as b on a.zw_id=b.zw_id left join zw as c on a.man_id=c.man_id -- 同时关联zw字段,通过表别名区别开 left join xb as d on c.sex_id=d.sex_id 作者:dxnn520 发表于2013-2-26 9:36:06 原文链接 阅读:29 评论:0 查看评论